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Yanka [14]
3 years ago
8

Need helppp.........​

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

Pls attach a picture so we can help

Step-by-step explanation:

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Answer:

216

Step-by-step explanation:

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Which expressions are equivalent to the given sort 40 (there is more than one and the one selected is correct)
Basile [38]

Answer:

40 {}^{ \frac{1}{2} }

Step-by-step explanation:

The last one is also the answer

Using the rational exponet rule,

\sqrt[n]{ {x}^{m} }  = x {}^{ \frac{m}{n} }

Using this number,

\sqrt{40}

40 is the base so it will stay same. Remember this is a square root sign so our nth root is 2 so our denominator if the rational exponet is 2.

40 {}^{1}  = 40

so our numerator is 1 so

40 {}^{ \frac{1}{2} }

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3 years ago
A pipe is leaking at the rate of 32 fluid ounces per minute. Use dimensional analysis to find out how many gallons the pipe is l
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well first think about it, 60 min in an hour, so 32 fluid ounces times 60 = 1920 fluid ounces, from there you can convert fluid ounces to practically anything, for instance, 1920 fluid ounces = 24 cups.

go to this address to find out more.

https://www.google.com/search?q=another+name+for+observations&rls=com.microsoft:en-US:IE-Address&ie=...

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3 years ago
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How would you measure the volume of a cardboard shoebox
Nina [5.8K]

-- Measure the length of the box.
-- Measure the width of the box.
-- Measure the height of the box.
-- Make sure all 3 measurements are in the same units.

-- Multiply (length) x (width).

-- Take that answer and multiply it by (height).

-- You now have the volume of the box.

6 0
3 years ago
A particle moves along the x-axis so that at any time t, t ≥ 0, its acceleration is a(t) = -4sin(2t). If the velocity of the par
sasho [114]

The velocity of the particle is given by

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

Since a(t)=-4\sin2t and v(0)=7, we get

\displaystyle\int_0^ta(u)\,\mathrm du=\int_0^t-4\sin2u\,\mathrm du=2\cos2u\bigg|_0^t=2\cos2t-2

\implies v(t)=2\cos2t+5

Similarly, the position function is obtained via

x(t)=x(0)+\displaystyle\int_0^tv(u)\,\mathrm du

We know v(t) and we're told that x(0)=0, so

\displaystyle\int_0^tv(u)\,\mathrm du=\int_0^t(2\cos2u+5)\,\mathrm du=\sin2u+5u\bigg|_0^t=\sin2t+5t

\implies x(t)=\sin2t+5t

making the answer A.

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