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Veseljchak [2.6K]
3 years ago
10

Keeping in mind the various definitions of operating system, consider whether the operating system should include applications s

uch as web browsers and mail programs. Argue both that it should and that it should not, and support your answers.
Computers and Technology
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

<em>it</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>group</em><em> </em><em>of</em><em> </em><em>Web</em><em> </em><em>pages</em><em> </em>

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JAVA
butalik [34]

Answer:

import java.util.*;

public class MyClass {

   public static void main(String args[]) {

       Scanner input = new Scanner(System.in);

       System.out.print("Input a word: ");

       String userinput = input.nextLine();

       for(int i =0;i<userinput.length();i+=2) {

           System.out.print(userinput.charAt(i));

       }

   }

}

Explanation:

This line prompts user for input

       System.out.print("Input a word: ");

This declares a string variable named userinput and also gets input from the user

       String userinput = input.nextLine();

The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2

       for(int i =0;i<userinput.length();i+=2) {

This prints characters at i-th position

           System.out.print(userinput.charAt(i));

5 0
2 years ago
Inc AX,2 is valid in assembly language ?
masya89 [10]

Answer:

in most so yes

Explanation:

4 0
2 years ago
Why don't I have friends?
Papessa [141]

Answer:

maybe you do not ask for them i will be your friend.

Explanation:

7 0
3 years ago
Read 2 more answers
A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, an
yulyashka [42]

The question is incomplete. It can be found in search engines. However, kindly find the complete question below:

Question

Cites as a pitfall the utilization of a subset of the performance equation as a performance metric. To illustrate this, consider the following two processors. P1 has a clock rate of 4 GHz, average CPI of 0.9, and requires the execution of 5.0E9 instructions. P2 has a clock rate of 3 GHz, an average CPI of 0.75, and requires the execution of 1.0E9 instructions. 1. One usual fallacy is to consider the computer with the largest clock rate as having the largest performance. Check if this is true for P1 and P2. 2. Another fallacy is to consider that the processor executing the largest number of instructions will need a larger CPU time. Considering that processor P1 is executing a sequence of 1.0E9 instructions and that the CPI of processors P1 and P2 do not change, determine the number of instructions that P2 can execute in the same time that P1 needs to execute 1.0E9 instructions. 3. A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, and consider that the processor with the largest MIPS has the largest performance. Check if this is true for P1 and P2. 4. Another common performance figure is MFLOPS (millions of floating-point operations per second), defined as MFLOPS = No. FP operations / (execution time x 1E6) but this figure has the same problems as MIPS. Assume that 40% of the instructions executed on both P1 and P2 are floating-point instructions. Find the MFLOPS figures for the programs.

Answer:

(1) We will use the formula:

                                       CPU time = number of instructions x CPI / Clock rate

So, using the 1 Ghz = 10⁹ Hz, we get that

CPU time₁ = 5 x 10⁹ x 0.9 / 4 Gh

                    = 4.5 x 10⁹ / 4 x 10⁹Hz = 1.125 s

and,

CPU time₂ = 1 x  10⁹ x 0.75 / 3 Ghz

                  = 0.75 x 10⁹ / 3 x 10⁹ Hz = 0.25 s

So, P2 is actually a lot faster than P1 since CPU₂ is less than CPU₁

(2)

     Find the CPU time of P1 using (*)

CPU time₁ = 10⁹ x 0.9 / 4 Ghz

                = 0.9 x 10⁹ / 4 x 10⁹ Hz = 0.225 s

So, we need to find the number of instructions₂ such that  CPU time₂ = 0.225 s. This means that using (*) along with clock rate₂ = 3 Ghz and CPI₂ = 0.75

Therefore,   numbers of instruction₂ x 0.75 / 3 Ghz = 0.225 s

Hence, numbers of instructions₂ = 0.225 x 3 x  10⁹ / 0.75  = 9 x 10⁸

So, P1 can process more instructions than P2 in the same period of time.

(3)

We recall  that:

MIPS = Clock rate / CPI X 10⁶

  So, MIPS₁ = 4GHZ / 0.9 X 10⁶ = 4 X 10⁹HZ / 0.9 X 10⁶ = 4444

        MIPS₂ = 3GHZ / 0.75 X 10⁶ = 3 x 10⁹ / 0.75 X 10⁶ = 4000

So, P1 has the bigger MIPS

(4)

  We now recall that:

MFLOPS = FLOPS Instructions / time x 10⁶

              = 0.4 x instructions / time x 10⁶ = 0.4 MIPS

Therefore,

                  MFLOPS₁ = 1777.6

                  MFLOPS₂ = 1600

Again, P1 has the bigger MFLOPS

3 0
2 years ago
Edhesive 3.3 lesson practice
den301095 [7]

Answer:

Consider the following code:

if (x > 5 AND x <= 10):

   print(OK)

Click all the mistakes that apply:

AND should be and

The print (OK) should be print ("OK")

The blue section of the following Venn diagram could represent which of the following Boolean statements?

not

The following code will not compile. Which of the options below would allow the code to compile and run as intended?

if (x >= -10 and <= 10):

   print("In range")

if (x >= -10 and x <= 10):

5 0
2 years ago
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