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3 years ago

How many different ways can 4 tickets be selected from 50 tickets if each ticket wins a different prize?

Mathematics

2 answers:

Masteriza [31]3 years ago

7 0

Answer:

5,527,200 ways can 4 tickets be selected from 50 tickets

Step-by-step explanation:

Given,

Total tickets = 50,

Number of tickets have to choose = 4,

Thus, the total ways of selecting 4 tickets out of 50 tickets = P(50, 4)

$=\frac{50!}{(50-4)!}$

$=\frac{50!}{46!}$

$=50\times 49\times 48\times 47$

$=5527200$

valkas [14]3 years ago

6 0

50P4 = 50!/(50-4)! = 50!/46! = 5,527,200 ways

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Step-by-step explanation:

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sasho [114]

Answer:

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Step-by-step explanation:

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We want to find the distance between the points (2, -2) and (-4, 7).

To do that, we can use the distance formula.

The distance formula is given as $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything needed to find the distance, but let's label the values of the points to avoid any confusion

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Now substitute those values into the formula and solve

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Add the numbers under the radical together

$\sqrt{117}$

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Hope this helps!

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