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3 years ago

How many different ways can 4 tickets be selected from 50 tickets if each ticket wins a different prize?

Mathematics

2 answers:

Masteriza [31]3 years ago

7 0

Answer:

5,527,200 ways can 4 tickets be selected from 50 tickets

Step-by-step explanation:

Given,

Total tickets = 50,

Number of tickets have to choose = 4,

Thus, the total ways of selecting 4 tickets out of 50 tickets = P(50, 4)

$=\frac{50!}{(50-4)!}$

$=\frac{50!}{46!}$

$=50\times 49\times 48\times 47$

$=5527200$

valkas [14]3 years ago

6 0

50P4 = 50!/(50-4)! = 50!/46! = 5,527,200 ways

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Volgvan

Answer:

p = -6.5

Step-by-step explanation:

Given:

18+ 2 (3p – 8) = –37

Solving for p:

18+ 2 (3p – 8) = –37
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Answer:

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3 years ago

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astraxan [27]

Answer:

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Step-by-step explanation:

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3 years ago

Hector is flying a kite. He has let out 86 feet

Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

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Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = $\frac{opposite}{hypotenus}$

Sin $42.26^{0}$ = $\frac{x}{86}$

⇒ x = 86 x Sin $42.26^{0}$

= 86 x 0.6725

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= 57.84 + 4

= 61.84 feet

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3 years ago