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konstantin123 [22]
3 years ago
6

What is the interquartile range of the data set?

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

The interquartile range of the data set will be 30.

<u><em>Explanation</em></u>

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, <u><em>30</em></u>, 40, 40, 48, 50, 55, <u><em>60</em></u>, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30




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The figure shows a cylinder of diameter 12cm and height = 15cm. A hole in the shape of cone is bored into one of its end. If the
Lisa [10]

Answer:

\bold{495\pi} \approx \bold{1555.088 cm^3}

Step-by-step explanation:

There was no figure but the question is clear

Volume of a cylinder is given by the formula \bold{\pi r^2h}\\

where r is radius of base of cylinder, h is the height

Volume of a cone is given by \bold{\frac{1}{3} \pi r^2 h}

where r is the radius of base of cone, h is the height

The radius of the cylinder = \frac{1}{2}(diameter) = \frac{1}{2}(12) = 6cm

Height of cylinder = 15cm

Volume of cylinder V_{cyl} = \pi (6)^2  15 = \pi (36)15 = \bold{540\pi}

Radius of cone = \frac{1}{2} (radius of cylinder) = \frac{1}{2}(6) = 3 cm

Height of cone same as height of cylinder = 15cm

Volume of cone, V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 =  \frac{1}{3}(9)15\pi = \bold{45\pi}\\


Difference is the volume of the remaining solid

V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}



5 0
2 years ago
In Part C, you determined that the proper ratio of packages of buns, packages of patties, and jars of pickles is 3:2:4. If you w
aivan3 [116]

Answer: packages of buns: 100

              packages of patties: 67

               jars of pickles: 133

(100,67,133)

Step-by-step explanation: packages of buns: B

                                            packages of patties: P

                                            jars of pickles: J

B:P:J = 3:2:4

B + P + J = 300

Let x be the number we must multiply the numbers to obtain the quantity and keep the ratio.

Bx + Px + Jx = 300

3x + 2x + 4x = 300

x = 300/9

So,

3.300/9 = 100

2.300/9 = 66.6666

4.300/9 = 133.333

As we cannot buy 0.666 or 0.33 of patties and pickles, we round up

So: packages of buns: 100

              packages of patties: 67

               jars of pickles: 133

7 0
3 years ago
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Answer:

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Simplify 9 − (−4). (1 point) a −13 b −5 c 5 d 13
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Answer:

d 13

Step-by-step explanation:

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To subtract -4, you add the opposite of -4 which is 4, so you add 4.

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Answer: d 13

7 0
3 years ago
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