Answer:
Step-by-step explanation:
-47.25
Answer:


![Interval = [666.78, 781.62]](https://tex.z-dn.net/?f=Interval%20%3D%20%5B666.78%2C%20781.62%5D)
Step-by-step explanation:
Given
The data for 25 undergraduates
Solving (a): Range and Standard deviation
The range is:

From the dataset:


So:



The standard deviation is:

First, calculate the mean



So, the standard deviation is:




Solving (b): The interval of the 95% of the observation.
Using the emperical rule, we have:
![Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]](https://tex.z-dn.net/?f=Interval%20%3D%20%5B%5Cbar%20x%20-%202%2A%5Csigma%2C%20%5Cbar%20x%2B%202%2A%5Csigma%5D)
![Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]](https://tex.z-dn.net/?f=Interval%20%3D%20%5B724.2%20-%202%2A28.71%2C%20724.2%20%2B%202%2A28.71%5D)
![Interval = [666.78, 781.62]](https://tex.z-dn.net/?f=Interval%20%3D%20%5B666.78%2C%20781.62%5D)
Answer:
pink
Step-by-step explanation:
zludzlzl7zos9rsofsorsorsirsira9ea9aors
Answer:
Well, just being simple, 2 would be the compass or the straightedge.
Step-by-step explanation:
Data with a mean that is over 94% (or 90 depending on the grading scale).
each grade you get is a point of data that when added together and getting the mean is over the threshold of "A"