2x + 6y = 14y - 19x^2 + 12 is a non-linear equation
Step-by-step explanation:
Lets define a linear equation first.
A linear equation is an equation in which there is no variable with exponent greater than 1 or the degree of the equation is 1.
So,
<u>x + 12 = -8x + 10 - 2y</u>
The equation is a linear equation because the degree of the equation is 1.
<u>x = 8x + 19 - 10y</u>
The equation is a linear equation because the degree of the equation is 1.
<u>2x + 6y = 14y - 19x^2 + 12</u>
The equation involve a term with exponent 2 which makes the degree of the equation 2 making it a quadratic equation
<u>2x + 13y + 14x - 7 = 16y - 3</u>
The equation is a linear equation because the degree of the equation is 1.
Hence,
2x + 6y = 14y - 19x^2 + 12 is a non-linear equation
Keywords: Linear, quadratic
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Answer:
(1/2 ,3) or (0.5, 3) is the same
Step-by-step explanation:
The midpoint between (3,5) and (-2,1) would be:
Apply the formula:
x1+x2 / 2 , y1 + y2 / 2
= 3 + (-2) / 2, 5 + 1 /2
= 1/2, 6/2
= 1/2 ,3 or 0.5, 3 is the same
Hope this helped :3
The answer is D
To solve the answer you would have needed to multiply the reciprocal of 
but in this case, Unvi multiplied with the reciprocal of 14.
Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.
The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.
If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.
n = 4
y = 2^(2*4)
y = 2^8
y = 256
n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.
so y = 2^(2n) I think is an exponential function.
Sorry my explanation is so long.
