Question

Possible values of x in 6x^2 + 432 = 0

Answer 1

$6x^2 + 432 = 0 \\ x^2+72=0\\ x^2=-72\\ x=-\sqrt{-72} \vee x=\sqrt{-72}\\ x=-6\sqrt2 i \vee x=6\sqrt 2 i$