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irina [24]
4 years ago
9

Possible values of x in 6x^2 + 432 = 0

Mathematics
1 answer:
Wewaii [24]4 years ago
3 0
6x^2 + 432 = 0 \\
x^2+72=0\\
x^2=-72\\
x=-\sqrt{-72} \vee x=\sqrt{-72}\\
x=-6\sqrt2 i \vee x=6\sqrt 2 i

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