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3 years ago

Convert units of time Convert 5 hrs to seconds.

Mathematics

2 answers:

emmasim [6.3K]3 years ago

6 0

Answer:

<h2>18000 seconds!</h2>

Step-by-step explanation:

<h2><u>5 hours is 18000 seconds!</u></h2>

GaryK [48]3 years ago

6 0

Answer:

18000

Step-by-step explanation:

There are 60 seconds in an min and 60 mins in an hours therefore if you multiply the time value by 3600 you get 18000 seconds in 5 hours.

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Let f (x)=2x-1 ,g (x)=3x,solve g (f (x))

Zolol [24]

G(x) = 3x
g(x) = 3*( x )
g(f(x)) = 3*( f(x) ) ... every x has been replaced with f(x)
g(f(x)) = 3*( 3x ) ... replace the f(x) on the right side with 3x
g(f(x)) = (3*3)x
g(f(x)) = 9x

8 0

3 years ago

Tyshon’s age is 3 less than three times Cedric’s age. The sum of their ages is 57. How old is Tyshon?

Airida [17]

Let Cedric's age be c
tyshon= 3c-3
3c-3 +c =3c+c-3 = 4c-3
4c-3=57
4c=60
c=15
tyshon=15×3-3 = 42

8 0

3 years ago

7/8x-5/8x fractional coefficients

Karolina [17]

Answer:

<em>x</em>/4

Step-by-step explanation:

7/8x-5/8x fractional coefficients = x/4

4 0

3 years ago

Read 2 more answers

Name the points that are a distance of 5 units from d

cupoosta [38]

WE NEED THE FREAKIN' POINTS

4 0

3 years ago

Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: $y=a(x-h)^{2} +k$

a: 1

h: 3

k: -25

$y=(x-3)^{2} -25$

Hope this helps!

3 0

3 years ago