If G is the midpoint of FH find FG
fg=11x-7 gh= 3x+9
Slope intercept form is y = mx+b, so you can see that you set the equation equal to y. So if the equation is 2y+3x=6, then you solve for y to put it in slope intercept form.
2y + 3x = 6
2y = -3x + 6
y = (-3/2)x + 3
Keep in mind that the term with the x has to be before the constant, so it can't be y = 3 -(3/2)x
And by the way m is the slope and b is y-intercept, so in <span>y = (-3/2)x + 3, -3/2 is slope and (0,3) is y-intercept</span>
Answer:
Question 3: B
Question 4: A, D, E
Step-by-step explanation:
Polynomials can not have a variable appear in the denominator.
4b^4-9b+2, 2x+7, and x-3 are in standard form.
there is an equation for straight lines which goes
y-y,=m(x-x,)
where( x, , y, ) is any coordinate on the line and m is the gradient
so your answer is
y-7= -2(x-4)
does this make sense?
