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mestny [16]
3 years ago
10

The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the seco

nd number is 97 find the numbers
Mathematics
1 answer:
jeyben [28]3 years ago
6 0

Answer:

Below in bold.

Step-by-step explanation:

x^2 - y^2 = 11

2x^2  + y^2 = 97

From the first equation:

y^2 = x^2 - 11

Substituting in the second equation:

2x^2 + x^2 - 11 = 97

3x^2 = 108

x^2 = 36

x = 6, -6.

Substituting  for x in the first equation:

(6)^2 - y^2 = 11

y^2 = 36 - 11 = 25

y = 5, -5.

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▹ Answer

<em>y = 15, -15</em>

▹ Step-by-Step Explanation

This is considered a 'square root' since we have to find y^2.

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Both of these values work for y, so the answer is 15, -15.

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4 0
3 years ago
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Given the data set (200,150,325,100,75) find the mean of the data set
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To find the mean (average), u add up all the numbers, then divide by how many numbers there are.

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7 0
3 years ago
Danni thinks of a number. She subtracts 2 then multiples the result by 8. The answer is the same as subtracting 5 from the numbe
Elena L [17]

Answer:

8

Step-by-step explanation:

let the number=x

8(x-2)=16(x-5)

divide by 8

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8 0
1 year ago
If f(x) =7x+5/3-x, then show that fof power -1(x) is an identity function ​
Irina-Kira [14]

If f(X)= 7x +5/3 - x =6x +5/3

y= 6x +5/3

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