The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the seco nd number is 97 find the numbers
1 answer:
Answer:
Below in bold.
Step-by-step explanation:
x^2 - y^2 = 11
2x^2 + y^2 = 97
From the first equation:
y^2 = x^2 - 11
Substituting in the second equation:
2x^2 + x^2 - 11 = 97
3x^2 = 108
x^2 = 36
x = 6, -6.
Substituting for x in the first equation:
(6)^2 - y^2 = 11
y^2 = 36 - 11 = 25
y = 5, -5.
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<em>Hope this helps </em>
<em>-Amelia </em>
Ok so 24 of them and that would be ur answer
Answer:
i didn't learn algebra or geometry or spatial sense when i was in sixth grade
Step-by-step explanation:
13 divided by 11.3 is 1.150442477876106. So 15 by 1.150442477876106 and you get 13.03846162772485. Just round it to the nearest tenth and you get 13.0.
