Answer : C
hope that helps
Answer:
a) d²y/dx² = ½ x + y − ½
b) Relative minimum
Step-by-step explanation:
a) Take the derivative with respect to x.
dy/dx = ½ x + y − 1
d²y/dx² = ½ + dy/dx
d²y/dx² = ½ + (½ x + y − 1)
d²y/dx² = ½ x + y − ½
b) At (0, 1), the first and second derivatives are:
dy/dx = ½ (0) + (1) − 1
dy/dx = 0
d²y/dx² = ½ (0) + (1) − ½
d²y/dx² = ½
The first derivative is 0, and the second derivative is positive (concave up). Therefore, the point is a relative minimum.
To find the gradient of a line you use this equation: Rise / Run
I am assuming this is a graph where both the x and y-axis increase in value by one.
So first of all, you should draw out this graph.
Second, draw a point at each of the given coordinates.
Now, join these points by drawing a right angle triangle. Put simply, draw a line from the point (4, -7) down until it is on the same level as the point (2, -3), then draw a line across.
Finally, measure the length of both these sides and use them in the equation above.
Let's assume the rise (vertical line) and the run (horizontal line) are 5 and 8 respectively. We can do 5/8 to get a gradient which is 0.625.
Answer:
15.8333333333
Step-by-step explanation:
9.5 divied by 3.5
Answer:
Step-by-step explanation:
√-80