Question

2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2vvvv

Answer 1

Since 4 circles are circumscribed by a square, then the side length of the square is 8

So the area of the square is 8^2 = 64

The area of 4 squares is 4 * pi*2^2 = 16pi

So the answer will be 64 - 16pi

Answer 2

Answer: $64-16\pi$ unit square.

Step-by-step explanation:

Here, four circle are removing from a square from the square of edge 8.

Since, The area of the square= $8^2=64$ square unit  ( because, area of square=side×side)

The area of a circle with radius 2 = $\pi(2)^2=4\pi$ square unit.

The area of four circle of radius 2= $4\times4\pi=16\pi$ square unit.

According to the question, these four circle are removed by the above square.

Therefore remaining area of the square after removing these four circle=area of the square- area of four circle of radius 2= $64-16\pi$ square unit.