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irakobra [83]
3 years ago
15

A surveyor measures the angle of elevation

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0

Check the picture below.

make sure your calculator is in Degree mode.

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You roll one die. What is the probability that you roll a 6?
professor190 [17]
The probability of rolling any one number in the sample space {1, 2, 3, 4, 5, 6}
is 1/6
LETTER C
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3 years ago
A greater number than -8​
sertanlavr [38]
Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9
6 0
3 years ago
Learning Task II. Illustrate the following: Illustration Given 1. Line Segment MN 2. Ray XY 3. Ray YX 4. Angle ABC 5. LK​
Mashutka [201]

The illustration of the given mathematical elements is as in the attached images.

<h3>Illustration of mathematical elements</h3>

For line segments;

  • The beginning and end of the line are specified by the assigned alphabets.

However, for rays;

  • The ray is illustrated to originate from a point and span on from there till infinity.

For angles;

  • The alphabet in the middle of the set of 3 alphabets used to identify the angle represents the center point of where the angle is located.

Read more on illustration of mathematical elements;

brainly.com/question/18430725

6 0
2 years ago
Evaluate the function. f(x) = 3x² – x Find f(10)​
kirill [66]

Answer:

<em>f(10)=290</em>

Step-by-step explanation:

<u>Function Evaluation</u>

Given a function f(x) as an explicit expression, finding f(x=a) implies substituting the value of x by a in every instance it occurs.

We are given the function:

f(x)=3x^2-x

It's required to find f(10). We replace the x for 10:

f(10)=3*10^2-10

Operating:

f(10)=3*100-10

f(10)=300-10

f(10)=290

Thus, f(10)=290

4 0
3 years ago
ASAP I NEED HELP
alexdok [17]

The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:

y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.

Substituting the given info into the equation y-k = a(x-h)^2, we get:

3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is

y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.

7 0
3 years ago
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