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3 years ago

15

A health club charges $35 a month for membership fees. Determine whether the cost of membership is proportional to the number of

months. Explain your reasoning.

1 answer:

Ivanshal [37]3 years ago

5 0

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I NEED UR HELPFNGKFNKFJFF

alisha [4.7K]

For Q3, you can subsitute x = 2 and y = 5 into the systems

-5(2) + 5 = -5

so it's a solution for the first system

-4(2)+2(5) = 2

it's also a solution for the second system

8 0

2 years ago

What is the equation of the line perpendicular to 3x+y=6 that passes through the point (0,8)

Alekssandra [29.7K]

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$3x + y = 6$

$y = - 3x + 6$

The coefficient of x is the slope of the line , So the slope of the above equation is -3 .

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Remember from now on ,

Product of multiplying the slopes of two lines which are perpendicular to each other , is -1 .

Thus ;

$( - 3) \times (m) = - 1$

m is the slope of the line which we want.

$- 3m = - 1$

Negatives simplifies

$3m = 1$

Divide sides by 3

$\frac{3m}{3} = \frac{1}{3} \\$

$m = \frac{1}{3} \\$

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We have following equation to find the point-slope form of the linear functions :

$y - y(0) = m(x - x(0))$

x(0) and y(0) are the coordinates of the point which the line passed through.

$y - 8 = \frac{1}{3} (x - 0) \\$

$y - 8 = \frac{1}{3} x \\$

Add sides 8

$y = \frac{1}{3} x + 8 \\$

Done....

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6 0

2 years ago

Please answer the question above.

Crank

Answer:

Waffle house :3

Step-by-step explanation:

8 0

2 years ago

Which is the center of a circle whose equation is x2+y2+4x-8y+11=0?

Nikolay [14]

Answer:

Center (-2 , 4)

Step-by-step explanation:

x^2 + 4x + y^2 - 8y = - 11

(x^2 + 4x + (4/2)^2 + (y^2 - 8y + (8/2)^2 ) = - 11 + 4 + 16

(x + 2)^2 + (y - 4)^2 = 9

Center (-2, 4)

6 0

2 years ago

Find the exact value of tan(165°) using a difference of two angles

Katyanochek1 [597]

Answer: $-2+\sqrt{3}$

=========================================================

Work Shown:

Apply the following trig identity

$\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\$

Now let's rationalize the denominator

$\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\$

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

$\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949$

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as $\sqrt{3}-2$ but it's the same as above.

5 0

2 years ago