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sergeinik [125]
3 years ago
11

Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me

asured their heights with the resulting relative frequency distribution as shown here. identify two major flaws with these results. height​ (cm) relative frequency 130dash–144 2222​% 145dash–159 2424​% 160dash–174 2121​% 175dash–189 2626​% 190dash–204 2828​%
Mathematics
2 answers:
gogolik [260]3 years ago
8 0
From the table the major flaws that can be identified are:
1. The sum of the relative frequencies of the dat set is greater than 100% which is not possible.
For any dataset, the sum of the relative freduency must be 100%

2.) the distribution of the data is not symmetric.
8090 [49]3 years ago
3 0

Answer:

The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.

Step-by-step explanation:

The sum of the probabilities of a distribution should be 100%.  When you add the probabilities of this distribution together, you have

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This is more than 100%, which is a flaw with the results.

A normal distribution is a bell-shaped distribution.  Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.

The bars would not create a bell-shaped curve; thus this is not a normal distribution.

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The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

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We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

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Hense:

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5 0
2 years ago
The length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle
pentagon [3]
The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
</span>2w = p - 2l
w = (<span>p - 2l</span>)/2
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Step-by-step explanation:

If a pack contain 1 2/3 pounds, 7 packs would contain :

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8 0
2 years ago
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All you have to do here is to multiply both sides of this equation by 13.  This will eliminate the fractions.  You'll be left with V = 11.

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