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balu736 [363]
3 years ago
9

PLEASE HELP !!! I WILL MARK BRAINLIEST

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0
I’m sorry, wait I think I know.... let me think.. no I’m so sorry. Ask google
My name is Ann [436]3 years ago
5 0

Answer:

wats the question

Step-by-step explanation:

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   Answer  : 35

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Tell me which 4 letters are right! A? B? C? D? F? E? I WILL GIVE BRAINLIEST
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Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Two methods, A and B, are available for teaching a certain industrial skill. The failure rate is 35\% for A and 15\% for B. Howe
valentina_108 [34]

Answer:

Therefore the probability that he was taught by method A is 0.78.

Explanation:

<h3>Probability:</h3>

The ratio of the number of favorable outcomes to the number of all possible outcomes.

<h3>Bayes' Rule:</h3>

If the events B_1,B_2, .....B_n from a portion of a sample space S and A is any events of A, then

P(B_i|A)=\frac{P(B_i)P(A|B_i)}{\sum_{j=1}^kP(B_j)P(A|B_j)}

Given that,

There are two available method for teaching A and B.

The failure rate for A is 35%

That is P(F|A) =35%=0.35

The failure rate for B is 15%

That is P(F|A) =15%=0.15

A used 40% of the time.

P(A)=40%=0.40

B used 60% of the time.

P(A)=60%=0.60

To find P(A|F) , we use the Bayes's rule.

P(A|F)=\frac{P(A)P(F|A)}{P(A)P(F|A)+P(B)P(F|B)}

            =\frac{0.60\times 0.35}{0.60\times 0.35+0.40\times 0.15}

           =0.78

Therefore the probability that he was taught by method A is 0.78.

4 0
3 years ago
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