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balu736 [363]
3 years ago
9

PLEASE HELP !!! I WILL MARK BRAINLIEST

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0
I’m sorry, wait I think I know.... let me think.. no I’m so sorry. Ask google
My name is Ann [436]3 years ago
5 0

Answer:

wats the question

Step-by-step explanation:

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I think it's 90 degrees
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Jonah wants to construct a confidence interval using 90% confidence to estimate what proportion of silicon wafers at his factory
Nimfa-mama [501]

Answer:

170

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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In which

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The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

What is the smallest sample size required to obtain the desired margin of error?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.06*0.94}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.06*0.94}

\sqrt{n} = \frac{1.645\sqrt{0.06*0.94}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.06*0.94}}{0.03})^2

n = 169.6

Rounding up, 170.

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3 years ago
Directions: Factor each polynomial. Look for a GCF first
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Here are the answer to your question

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4. 4



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