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BabaBlast [244]
3 years ago
12

Solve (2x+3) (x+4)= 1

Mathematics
1 answer:
Digiron [165]3 years ago
5 0

To solve, simply layout an equation.

(2x+3)(x+4)=1

Step 1: Simplify both sides of the equation.

2x2+11x+12=1

Step 2: Subtract 1 from both sides.

2x2+11x+12−1=1−1

2x2+11x+11=0

Step 3: Use quadratic formula with a=2, b=11, c=11.

x=-b±√b^2-4ac/2a

So, the answer for this problem is:

x=-11/4+1/4√33 or -11/4+-1/4√33

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lesya692 [45]

Your middle finger and index/pointer.

8 0
3 years ago
Read 2 more answers
Write an expression that is equivalent to three over four(5z + 16).
klio [65]
Your answer is B. Using the distributive property, 3/4 • 5z equals 15/4z, which can't be simplified. Then 3/4 of 16 is 12. If you divide 16 by 4 (the denominator) and then multiply by 3 (the numerator) that yields your answer.
8 0
3 years ago
Bryce tried to solve an equation step by step. \qquad\begin{aligned} \dfrac83&=3\left(c+\dfrac53\right)\\\\ \\ \dfrac83&
sesenic [268]

Answer:

Bryce is wrong in step 1 because he did not distribute 3 over 5/3

Explanation

Given the steps taken by bryce as shown, we are to find where he made an error

\qquad\begin{aligned} \dfrac83&=3\left(c+\dfrac53\right)\\\\ \\ \dfrac83&=3c+\dfrac53&\green{\text{Step } 1}\\\\ \\ 1&=3c&\blue{\text{Step } 2}\\\\ \\ \dfrac13&=c&\purple{\text{Step } 3}\\\\ \end{aligned}

Given the expression;

\dfrac83&=3\left(c+\dfrac53\right)\\\\ \\

Step 1:Expand the bracket using the distributive law;

8/3 = 3c + 3(5/3)

<em>Simplify</em>

8/3 = 3c + 15/3

Step 2: Subtract 15/3 from both sides

8/3 - 15/3 = 3c+15/3-15/3

(8-15)/3 = 3c

-7/3 = 3c

Step 3: Multiply both sides by 1/3

-7/3 * 1/3 = 3c * 1/3

-7/9 = c

Swap

c = -7/9

From the calculation, we can see that Bryce is wrong in step 1 because he did not distribute 3 over 5/3 thereby making his solution incorrect

3 0
2 years ago
I need help solving this problem
Ludmilka [50]
G(f(2)) means work out whatever f(2) is then plug this into g(x).

So f(2) is 3 because we just find the x-value 2 in the left hand column and read across. This is 3.

So then we find g(3) by finding the x-value 3 in the left hand column and read across. This is 10.

So g(f(2)) = 10
3 0
3 years ago
Rolands suitcase has a mass of 2,500 dekagrams. How many kilograms is his suitcase?
Tasya [4]
A decagram is 10 grams, so first lets convert the decagrams to grams and then after we'll change to kilograms.
If 1 decagram equals 10 grams, then 2500 decagrams is equal to:
2500*10 = 25000 grams
Now, 1 kilogram equals 1000 grams so 25000 grams equals:
25000/1000 = 25 kg
therefore, 2500 decagrams equals 25 kg
3 0
3 years ago
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