3 years ago

Round 5,836,197 to the nearest hundred

Mathematics

2 answers:

Nataly [62]3 years ago

7 0

Answer:

5836200

Step-by-step explanation:

arlik [135]3 years ago

6 0

Answer:

5836200.

Step-by-step explanation:

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3 years ago

How do you solve 1-5+1×(4×4-31)×8

Alja [10]

Hey there!

In order to solve this, remember PEMDAS. First, start with solving whatever is in parentheses. Then, move on to exponents. Then, complete the multiplication and division. Lastly, add or subtract anything remaining. Omit any steps that aren't present.

Parentheses:

<span>1 – 5 + 1 × (4 × 4 – 31) × 8
</span>1 – 5 + 1 × (–15) × 8

Multiplication/Division (Left to Right):

1 – 5 + (–15) × 8
1 – 5 + (–120)
1 – 5 – 120

Addition/Subtraction (Left to Right):

–4 – 120
–124

Your answer is –124.

Hope this helped you out! :-)

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3 years ago

? Question

Delvig [45]

Answer:

i^32=1

i^25=i

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Step-by-step explanation:

Follow the Rule of Four of I for this,

i^1= $\sqrt{-1}$

I^2=-1

I^3=-i

I^4=1

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