What is the solution of y=7x-3

Write the expression as a single natural logarithm 3 In b - 2 In a

Marta_Voda [28]

Answer:

We have ln(b^3) - ln(a^2) = ln(b^3/a^2);

Step-by-step explanation:

7 0

4 years ago

If y varies directly as x and y = 4 and x = 10, what does x equal when y = 7?

soldi70 [24.7K]

Answer: x = 17 $\frac{1}{2}$

Step-by-step explanation:

From the question: y α x

⇒ y = kx

y=4 and x = 10 implies

4 = 10k

k = 4/10

k = 2/5

substitute k = 2/5 into the equation

y = 2/5 x

When y = 7 , the equation becomes

7 = $\frac{2x}{5}$

35 = 2x

35/2 =x

Therefore : 17 $\frac{1}{2}$

x =

8 0

4 years ago

Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)

muminat

Answer:

The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = $\frac{-5}{2}$ x + $\frac{12}{2}$

Or, y = $\frac{-5}{2}$ x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = $\frac{-5}{2}$

Again,

The other line if passing through the points (- 2 , 3 ) And is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So, M = m = $\frac{-5}{2}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = $\frac{-5}{2}$ × ( - 2 ) + c

or, 3 = $\frac{10}{2}$ + c

Or, 3 = 5 + c

∴ c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope $\frac{-5}{2}$ and passing through points ( -2 , 3)

y = $\frac{-5}{2}$ x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And is perpendicular to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So, M' × m = - 1

Or, M' × $\frac{-5}{2}$ = - 1

Or, M' = $\frac{-1}{\frac{-5}{2}}$

Or, M' = $\frac{2}{5}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = $\frac{2}{5}$ × ( - 2 ) + c'

or, 3 = $\frac{- 4}{5}$ + c'

Or, 3 × 5 = - 4 + 5× c'

∴ 5 c' = 15 + 4

or, 5 c' = 19

Or, c' = $\frac{19}{5}$

So, The equation of line with slope $\frac{2}{5}$ and passing through points ( -2 , 3)

y = $\frac{2}{5}$ x + $\frac{19}{5}$

y = $\frac{2 x + 19}{5}$

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0

3 years ago

What's (-5, 3) reflected along x-axis

Anna71 [15]

Whenever you reflect a point over the x axis, the x coordinate stays the same and the y coordinate is negated. In this case, the y coordinate which is 3 will be negated to become -3, and the x coordinate which is -5 will remain the same. Therefore, the new point is (-5,-3).

I hope this helps.

4 0

3 years ago

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please do my last question u get more points if the answer is right. if inappropriate you get reported NO LINKS

Alisiya [41]

Answer:

1.35!

Step-by-step explanation:

Its 1.35 dollars :). hope you get it right

4 0

3 years ago

Read 2 more answers