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diamong [38]
3 years ago
9

5k-3(2k-2/3)-9=0. Solve the equation

Mathematics
1 answer:
yan [13]3 years ago
5 0

-7 is your answer to this equation

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Triangle ABC has vertices of A(-6,7) B(4,-1), and C(-2,-9). Find the length of the median from angle B in triangle ABC.
AfilCa [17]

The length of the median from angle B is 8.

4 0
3 years ago
A ratio of dogs to cats a pet store is 1:3. There are 15 cats. how many dogs are at the pet store
DIA [1.3K]

From the ratio given we know that there is 3 times more cats than dogs.

If there are 15 cats, then there are 15/3 dogs or 5 dogs.

answer: 5 dogs

8 0
3 years ago
Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 2.
raketka [301]

Answer:

2/6561

Step-by-step explanation:

Geometric sequence formula : a_n=a_1(r)^n^-^1

where an = nth term, a1 = first term , r = common ratio and n = term position

given ratio : 1/3 , first term : 2 , given this we want to find the 9th term

to do so we simply plug in what we are given into the formula

recall formula : a_n=a_1(r)^n^-^1

define variables : a1 = 2 , r = 1/3 , n = 9

plug in values

a9 = 2(1/3)^(9-1)

subtract exponents

a9 = 2(1/3)^8

evaluate exponent

a9 = 2 (1/6561)

multiply 2 and 1/6561

a9 = 2/6561

7 0
2 years ago
R + 3 1/2 = -4 2/3
alexandr402 [8]

Answer:

R = -8 1/6

Step-by-step explanation:

We'll solve the given equation for R.

Subtract 3 1/2 from both sides of the equation, to isolate R:

           R +  3 1/2  -  3 1/2 = -4 2/3  - 3 1/2, or

            R = -4 2/3 - 3 1/2

The LCD here is 6, which is the product of 3 and 2.  Converting the fractions to denominator 6, we get:

              R = -4 4/6 - 3 3/6, or

               R = -7 - 7/6, or R = -7 - 1 1/6, or -8 1/6

3 0
3 years ago
Can someone help me out with these problems and show work please !!
AVprozaik [17]

Answer:

13. 10a^4b²

14. -5y³ + 35y² - 10y

Step-by-step explanation:

Question 13:

(5a³b) (2ab) =

=10a^4b²

Question 14:

5y (-y² + 7y - 2) =

= -5y³ + 35y² - 10y

Hope this helps!

5 0
1 year ago
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