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poizon [28]
3 years ago
15

Ming plays video games online. When he signed up with the game site, Ming got 200 points. Ming earns 20 more points for each hou

r that he plays. How many hours does Ming have to play to get to 500 points?
Mathematics
2 answers:
vitfil [10]3 years ago
7 0

Answer:

Ming has to play for 15 hours to earn 500 points.

Step-by-step explanation:

1. Make an equation: 200 + 20h = 500 pts

2. 500 - 200 = 300

3. 300 / 20 = 15

h = 15 hours

Irina-Kira [14]3 years ago
3 0
First, substract the total of points with the points he got from signing up, to find the points he got after playing
points after playing = 500 - 200
points after playing = 300

Second, divide the points after playing by the number of points per hour, to find how long Ming played
time = 300/20
time = 15

Ming played for 15 hours
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Find the height of a right circular cone if the slant height is 4 units and the radius is 2 units
k0ka [10]

The slant height of the right circular cone will be  l=2\sqrt5}

<h3>What is slant height of cone? </h3>

The formula for the slant height of the cone is given as:

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By putting the values we will get

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7 0
2 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

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Which statement accurately explains whether a reflection over the x-axis and a 180° rotation would map figure ACB
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