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raketka [301]
3 years ago
11

Write a subtraction sentence using integers.than,write the equivalent addition sentence and explain how to find the sum.please h

elp me I am not smart.
Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

First option: 10 - (1) = 9

Second option: 10 - 5 + 4 = 5 + 4 = 9

Step-by-step explanation:

(10 -5) -4 = 5 - 4 = 1

Equivalent equation: 10 - 5 - 4 = 1

10 - (5-4) = there would be 2 ways to do this, you can either solve the equation in the bracket first or break it out. Because the sign before the bracket is minus so when you break it out, the minus sign in the bracket would become -- or equal to +

First option: 10 - (1) = 9

Second option: 10 - 5 + 4 = 5 + 4 = 9

Hope this help you:3

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Solve by factorization<br> 2x^2 + 3x -20 = 0
saul85 [17]

Answer:

x=2.5 or x=-4

Step-by-step explanation:

factorisation= factors:1, 2, 4, 5, 10, 20 (only the positive factors)

We will use the factors 4 and 5.

=(2x-5)(x+4)=0

2x-5=0   || x+4=0

2x=+5      || x=-4

x=2.5  or x=-4

4 0
3 years ago
Read 2 more answers
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
3. Express the mixed recurring decimal 15.732 in p/q form.​
Alborosie

Answer

15717/999

Step-by-step explanation

n=15.732732

10n=157.32732

100n=1573.27327

1000n=15732.732732

n= 15.732732

999n=15717

999 999

4 0
3 years ago
Read 2 more answers
If x=-4 and y=6, then xy-3=
Anna11 [10]

Answer:

-12

Step-by-step explanation:

We start with the equation: xy-3x

Substitute the variables: (-4)(6)-3(-4)

Solve using order of operations (start with multiplication): (-24)-(-12)

And then addition/subtration: (-24)-(-12)=-12

3 0
3 years ago
HELP ASAP.
8090 [49]

Hey there!

#1 ⬇️

6 × 6 × 6 × 6 × 6

6 × 6 = 36

36 × 36 × 6

36 × 36 = 1,296

1296 × 6 = 7,776

Answer: 7,776 ☑️

#2 ⬇️

3 × 3 × 3 × 3

3 × 3 = 9

9 × 9 = 81

Answer: 81 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
2 years ago
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