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n200080 [17]
3 years ago
14

The table shows the cost of a game from 2000 to 2004, which has been increasing in a quadratic fashion. Let x = 0 in 2000, and f

ind the best-fit quadratic equation. What will game cost in 2010? A) $417 Eliminate B) $746 C) $960 D) $1,586
Mathematics
1 answer:
Burka [1]3 years ago
5 0

Answer: Here we are going to use the equation y=15x2+3x+56.

x=0 in 2,000 so x=10 in 2010.  

Substitute 10 for x.

After this we have the answer: D. $1,586

<u>Hope this helps</u>

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The area of a rectangular field is 2275 m2. The field is enclosed by 200 m of fence. What are the dimensions of the field?
AURORKA [14]
So it is enclosed by 200 m of  fence
perimiter=200 m
it is a rectangle to
p=legnth+legnth+width+width or
p=l+l+w+w or
p=2l+2w or
p=2(l+w)
so
p=200
200=2(l+w)
divide both sides by 2
100=l+w
area=l times w
area=2275
lw=2275
l+w=100
combine and solve
l+w=100
subtract w
l=100-w
subisutute 100-w for l in other eqution
(100-w)(w)=2275
distribute
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add (w^2-100w) to both sides
0=w^2-100w+2275
factor
find what 2 numbers add up to -100 and multiply to get 2275
guess (or factor 2275 and find factors that add up to -100)
figure out that they are -65 and -35
0=(w-65)(w-35)
set each to zero
0=w-65
0=w-35

solve for w
w=65 or 35
65>35 so
65 m=legnth
35 m=width
 
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Write <br> 49%<br> as a fraction.
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......................

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My best Guess is

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Hope this Helps

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