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Sladkaya [172]
3 years ago
13

Write the following ratio using two other notations. 7:9 Use only the numbers above (not any others). WILL GIVE BRAINLIEST TO BE

ST ANSWER HEEELLLLLPPPPPPPP
Mathematics
1 answer:
aalyn [17]3 years ago
4 0

Answer:

Step-by-step explanation:

7:9

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Cost of sled $99.50 markup 95%
DIA [1.3K]
Sled $99.50 X 0.95= $94.525
$94.525+ $99.50 = $194.025
Answer is $194.03
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3 years ago
Logan owed his brother $7.50. For his birthday, Logan received $20 from his grandpa. After paying his brother back, how much mon
evablogger [386]

Answer:

$12.50

Step-by-step explanation:

20 - 7.50=12.50

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Each student on the trip to cooperstown paid the same amount .the tottal amount collected was $589.pilar paid for her ticket usi
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Answer:

$231.67

Step-by-step explanation:

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3 years ago
The following value is closest to what number? 292
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5 0
3 years ago
A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9
geniusboy [140]

Answer:

7.7 km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 6.6 km and 3.9 km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, a^{2}+b^{2} =c^{2}, where a and b are the lengths of the triangle's legs and c is the length of the triangle's hypotenuse. In this case, we know what a and b are, and we need to solve for c, so after substituting the given values of a and b into a^{2}+b^{2} =c^{2} to solve for c, we get:

a^{2}+b^{2} =c^{2}

6.6^{2} +3.9^{2} =c^{2} (Substitute a=6.6 and b=3.9 into the equation)

43.56+15.21=c^{2} (Evaluate the squares on the LHS)

58.77=c^{2} (Simplify the LHS)

c^{2}=58.77 (Symmetric Property of Equality)

\sqrt{c^{2} } =\sqrt{58.77} (Take the square root of both sides of the equation)

c=7.7,c=-7.7 (Simplify)

c=-7.7 is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately 7.7 km away from its base. Hope this helps!

7 0
3 years ago
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