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horrorfan [7]
3 years ago
13

Two integers a and B have a product of 24 what is the least possible sum of a and B

Mathematics
2 answers:
Serhud [2]3 years ago
8 0
The least possible sum is 6 and 4. If your having problems, write down the factors and choose the pair that adds up the smallest number :)
Bingel [31]3 years ago
5 0
6 and 4 you can do factors of 6: 6,12,18,24,
4: 4,8,12 16,20,24 both is 24 so that is the answer 6 and 4
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4 thousands + 21 tens
mafiozo [28]
4 x 1 thousand (1000) = 4000

21 x 1 ten (10) = 210


 4000
+ 210
---------
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=4210 (four thousand-two hundred and ten
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What is 5x^2+4x=80 times x^2-5x-24=0
Wittaler [7]
(5x²+4x-80)(x²-5x-24)=5x²(x²-5x-24)+4x(x²-5x-24)-80(x²-5x-24)
{distributive property of multiplication}
                                  =5x^4-25x³-120x²+4x³-20x²-96x-80x²+400x+1920
                                  =5x^4-21x³-220x²+304x+1920
This is the answer.
8 0
3 years ago
Select the correct answer from each drop-down menu.
tino4ka555 [31]

Answer:   The correct answer is:   [C]:  "  15^{(7/4)} " .

____________________________________

Step-by-step explanation:

____________________________________

Note the property for square roots in exponential form:

_____________________________________

     →    \sqrt[a]{(b)^ c}  ;  ↔  bb^{(c/a)} ;

    { a\neq 0 ; [a^{(b/c)}]\neq 0 ; c\neq 0  .}.

_____________________________________

As such, given:

     →    \sqrt[4]{(15^7)} ;  

  a = 15,  b = 7,  c = 4 .

     

     →    \sqrt[4]{(15^7)} ;   ↔  15^{(7/4)} ;

     →  which corresponds to:

_____________________________________

Answer choice:  [C]:  "  15^{(7/4)} " .

_____________________________________

Hope this helps!

  Wishing you well in your academic endeavors!

_____________________________________

5 0
3 years ago
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