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3 years ago

Determine the next term in the geometric sequence. -1, -6, -36, -216, ??

2 answers:

5 0

The sequence goes by decrements of multiples of 6 starting at -1

-1 * 6 = -6
-6 * 6 = -36
-36 * 6 = -216
-216 * 6 = -1296

nordsb [41]3 years ago

4 0

You are multiply by 6 each time.

The next term is -216 x 6

-216 x 6= -1296

-1296 is your answer

hope this helps

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Chen writes down a two digit number. He finds out that if he swapped the numbers, it would be three more than the 1/3 of the ori

inna [77]

Answer:

Step-by-step explanation:

From the information given,

Let the two digits that Chen writes down to be p and q

where,

q will be in the unit place and p will be in the tens place.

So, the value of the digit = 10p + q

So, if he swapped the number, he will have 10q + p

However,

the new number determined is thrice more than the 1/3 pf the original number.

i.e

the 1/3rd of the original number = $\dfrac{1}{3}(10p+q)$

= $\dfrac{10p+q}{3}$

thrice more than that will be = $\dfrac{10p+q}{3} + 3$

∴

$\dfrac{10p+q}{3} + 3 = 10q+p$

multiply through by 3, we have :

10p+q + 9 = 30q + 3p

collecting the like terms, we have:

10p - 3p +q -30q +9 = 0

7p - 29q +9 = 0

7p - 29q = -9

Therefore, p,q lie between 0 and 9

Therefore, the possibility of the original number is p = 7 and q = 2

8 0

3 years ago

Sam has 35 rubbers.He wants to share them equally between 3 of his friends .How many will each friend receive?How many are left

Nitella [24]

Answer:

11 will be shared out and there will be 2 rubbers left.

Step-by-step explanation:

the last number that 3 goes into before 35 is 33. 33 ÷ 3 = 11. So each friend gets 11 rubbers. then from 33, there will be 2 rubbers left.

5 0

3 years ago

Find the common difference for the sequence shown 1/4,5/16,3/8

Vladimir79 [104]

<span>common difference for the sequence = 1/16

cause
1/4 = 4/16
and
3/8 = 6/16

so
4/16 + 1/16 = 5/16
5/16 + 1/16 = 6/16

</span>

4 0

3 years ago

Find the Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in

Zielflug [23.3K]

Answer:

Σ(-1)^kx^k for k = 0 to n

Step-by-step explanation:

The nth Maclaurin polynomials for f to be

Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......

The given function is.

f(x) = 1/(1+x)

Differentiate four times with respect to x

f(x) = 1/(1+x)

f'(x) = -1/(1+x)²

f''(x) = 2/(1+x)³

f'''(x) = -6/(1+x)⁴

f''''(x) = 24/(1+x)^5

To calculate with a coefficient of 1

f(0) = 1

f'(0) = -1

f''(0) = 2

f'''(0) = -6

f''''(0) = 24

Findinf Pn(x) for n = 0 to 4.

Po(x) = 1

P1(x) = 1 - x

P2(x) = 1 - x + x²

P3(x) = 1 - x+ x² - x³

P4(x) = 1 - x+ x² - x³+ x⁴

Hence, the nth Maclaurin polynomials is

1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n

= Σ(-1)^kx^k for k = 0 to n

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3 years ago

Please help me find the area and perimeter of this composite figure.

pentagon [3]

Answer:

the area is 26 the perimetier is 52

Step-by-step explanation:

4 0

3 years ago

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