Question

In ΔJKL, the measure of ∠L=90°, JK = 7.3 feet, and KL = 4.7 feet. Find the measure of ∠J to the nearest tenth of a degree.

Answer 1

Answer:

40°

Step-by-step explanation:

We can find the  tangent of ∠J using the trigonometrical ratios which may be expressed in the form SOA CAH TOA Where,

SOA stands for

Sin Ф = opposite side/hypotenuses side

Cosine Ф = adjacent side/hypotenuses side

Tangent Ф = opposite side/adjacent side

The hypotenuse is the side facing the right angle while the opposite is the side facing the given angle.

Considering triangle ΔJKL, where ∠L=90°, JK = 7.3 feet, and KL = 4.7 feet

As such, with respect to angle J, JK is the hypotenuse, KL is the opposite side

Hence

Sin J = 4.7/7.3

Sin J = 0.643835616

J = 40.08°

Answer 2

Answer:

40.0°

Step-by-step explanation:

Given the triangle ∆JKL with the following measure

∠L=90°, JK = 7.3 feet, and KL = 4.7 feet.

In order find the angle ∠J, we will use the concept of SOH CAH TOA.

Since we are looking for the angle ∠J, our opposite side will be the side facing the angle ∠J directly.

Hypotenuse = JK = 7.3ft

According to SOH:

Sin ∠J = Opposite/Hypotenuse

Sin∠J = 4.7/7.3

Sin∠J = 0.644

∠J = arcsin 0.644

∠J = 40.0° to the nearest tenth of a degree