Answer:
x = 8
Step-by-step explanation:
Given
- 2(- 3x + 3) + 2x = 58 ← distribute and simplify left side
6x - 6 + 2x = 58
8x - 6 = 58 ( add 6 to both sides )
8x = 64 ( divide both sides by 8 )
x = 8
If the side length is greater than 11.11 cm then it will not overflow.
Otherwise, it will overflow.
If Joe tips the bucket of water in a cuboid container and the water is not overflowing then the cuboid container must be of volume greater than 1370 cm³.
We find the cube root of 1370 cm³.
![\sqrt[3]{1370} \approx11.11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1370%7D%20%5Capprox11.11)
Then the cuboid container should have a side of length greater than 11.11 cm.
Here the statement "If I tip my bucket of water in the cuboid container, it will never overflow" is correct or wrong based on the information that the container has a side length lesser or greater than 11.11 cm.
If the side length is greater than 11.11 cm then it will not overflow.
Otherwise, it will overflow.
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Answer:
$2.79 per pound of apple.
Step-by-step explanation:



Answer:
The mass of the object is 2.6 grams
Step-by-step explanation:
The density of an object is the ratio between its mass and its volume
The equation of the is d =
, where
Let us use this equation to solve the question
∵ An object has a density of 1.3 g/cm³
∴ d = 1.3 g/cm³
∵ Its volume is 2 cm³
∴ V = 2 cm³
→ Substitute them in the equation of the denisty above
∵ 1.3 = 
→ Multiply both sides by 2
∴ 2 × 1.3 = 2 × 
∴ 2.6 = m
∴ The mass of the object is 2.6 grams
Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²