Answer:
It's true
Step-by-step explanation:
I hope it helps you
<em>Y</em>₁ and <em>Y</em>₂ are independent, so their joint density is

By definition of conditional probability,
P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = P((<em>Y</em>₁ > <em>Y</em>₂) and (<em>Y</em>₁ < 2 <em>Y</em>₂)) / P(<em>Y</em>₁ < 2 <em>Y</em>₂)
Use the joint density to compute the component probabilities:
• numerator:






• denominator:

(I leave the details of the second integral to you)
Then you should end up with
P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = (1/6) / (2/3) = 1/4
Answer: The first number that appears in both sequences is 28.
Step-by-step explanation:
Let's write down numbers from each of the sequences
Sequence 1) We need to start from 7 and multiply 4
7x4=28, 28x4=112
The sequence is 7,28,112...
Sequence 2) We need to start from 8 and add 5
5+8=13, 13+5=18, 18+5=23, 23+5=28
The sequence is 8,13,18,23,28...
They both have 28
Answer:
0.8660254 or √3/2
Step-by-step explanation: