Can you help me please!!!!

Mathematics

2 answers:

Akimi4 [234]3 years ago

6 0

Answer:

y=mx+b

y=-2/5x -4

(-10,0),(-5,-2)

Step-by-step explanation:

Alexeev081 [22]3 years ago

4 0

Answer:

Step-by-step explanation:

(-10,0)(0,-4)

find slope

m=-2/5

b=-4

y=-2/5x-4

You might be interested in

Which table contains a set of coordinate points that is not a function?<br><br><br>PLS HELP

aleksandrvk [35]

Answer:

Step-by-step explanation:

-4 is listed twice with 2 different outputs

7 0

2 years ago

15x^4+6x^3-7x^2÷3x^2+1

pishuonlain [190]

$\\ \frac} }{38/3} x^{4} +6 x^{3} + 1=0$

5 0

3 years ago

What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−23x+5

elena-s [515]

Answer:

$y-1=\frac{1}{23} (x-8)$

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point (8,1) and a slope from the equation y=-23x+5. We will chose point-slope since we have a point and slope.

Point slope: $y-y_1=m(x-x_1)$

$m\neq -23$ in our new equation because it us perpendicular to it. This means we will need to change it into its negative reciprocal which is $m=\frac{1}{23}$ .