All categories

3 years ago

If f(x)=square root 4x+9+2, which inequality can be used to find the domain of f(x)?

Mathematics

2 answers:

jenyasd209 [6]3 years ago

8 0

we have

$f(x)=\sqrt{4x+9} +2$

we know that

The radicand must be greater than or equal to zero

$4x+9 \geq0 \\ 4x\geq -9 \\x\geq -\frac{9}{4} \\ x\geq -2.25$

the domain is is the interval--------> [-2.25,∞)

therefore

the answer is

$4x+9 \geq0$

elixir [45]3 years ago

7 0

4x + 9 ≥ 0
There is your answer

You might be interested in

Express the percent as a decimal. 30\%30%30, percent Stuck help

Marrrta [24]

If it’s 30% converted to a decimal it’ll be .30

3 0

3 years ago

Read 2 more answers

16 more than s is at most −80.

polet [3.4K]

Answer:

s + 16 ≤ −80

Step-by-step explanation:

Analyze each part in the word equation:

"16 more than s" s increased by 16; s + 16

"is at most" is equal to or less than; ≤

"−80" -80

Put the equation back together:

s + 16 ≤ −80

4 0

4 years ago

Evaluate 8 + 3e when e = 2. Need the Answer

alexandr402 [8]

Answer:

The answer is 14

Step-by-step explanation:

e=2

Substitute 2 in for e

8 + 3(2)

Solve

6 0

3 years ago

20 is what percent of 32 Write as an equation

AlladinOne [14]

20% of 32= 6.4

20% x 32

20 /100 x 32
Reduce the fraction
1 /5× 32
=32/5
=6.4

8 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

Supposing 60 out of 100 scores are passing scores, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

3 years ago