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Gnesinka [82]
3 years ago
8

The number of raffle tickets the student council sold over three days

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

104

Step-by-step explanation:

35+23+46= 104 total

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What is the center of a circle represented by the equation (x+9)^2+(y-6)^2=10
IRINA_888 [86]

Answer:

(-9,6)

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
.77 times 136.9 for dividing decimal worksheet thx!
ziro4ka [17]
Im going to attach a pic so it will be easier :)

8 0
3 years ago
When is factoring by grouping easier to use. How many terms must you have to have ?
Karo-lina-s [1.5K]
You must have 4 terms for factoring by grouping to be easier to use.

For example...
x^2 + 10x + 2x + 20
(x^2 + 10x) + (2x + 20)
x(x+10) + 2(x+10)
(x+2)(x+10)

The first line, the expression x^2+10x+2x+20, has four terms.

Note: Just because you have four terms doesn't automatically guarantee you can factor
3 0
3 years ago
What is the value of 4*(-1+2-3+4-3+6-7+....+100) Show your work. [Pls help I am really drowning in work. 50 points + brainliest
KengaRu [80]

Answer:

200

Step-by-step explanation:

We have:

4(-1+2-3+4-5+6-7...+100)

We can rearrange the numbers to obtain:

4((-1-3-5-7-...-99)+(2+4+6...+100))

From the left, we can factor out a negative. So:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

In other words, we want to find the sum of all the odd numbers from 1 to 99.

And the sum of all the even numbers from 2 to 100.

Let's do each one individually:

Odd Terms:

We have:

(1+3+5+7+...+99)

We can use the arithmetic series formula, where:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term.

Since it's all the odd numbers between 1 and 99, there are 50 terms.

Our first term is 1 and our last term is 99. So, the sum of all the odd terms are:

S=\frac{50}{2}(1+99})

Divide the fraction. Add within the parentheses:

S=25(100)

Multiply:

S=2500

So, the sum of all the odd terms is 2500.

Even Terms:

We have:

(2+4+6+...+100)

Again, we can use the above formula.

Our first term is 2, last term is 100. And since it's from 2-100, we have 50 even terms. So:

S=\frac{50}{2}(2+100)

Divide and add:

S=25(102)

Multiply:

S=2550

We originally had:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

Substitute them for their respective sums:

4(-(2500)+2550)

Multiply:

4(-2500+2550)

Add:

=4(50)

Multiply:

=200

So, the sum of our sequence is 200.

And we're done!

Note: I just found a <em>way</em> easier way to do this. We have:

4\cdot(-1+2-3+4-5+6-7+...+100)

Let's group every two terms together. So:

=4((-1+2)+(-3+4)+(-5+6)...+(-99+100))

We can see that they each sum to 1:

=4((1)+(1)+(1)+...+(1))

Since there are 100 terms, we will have 50 pairs, so 50 times 1. So:

=4(50)

Multiply:

=200

Pick which one you want to use! I will suggest this one though...

Edit: Typo

8 0
3 years ago
The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. The center of the target takes
Komok [63]
4%

To find the percentage, first find the area of both circles. The area formula is \pi  r^{2} . After finding the area of the center of the target (19.625) and the area of the large target (490.625), set up a percent proportion to determine the percentage that the center takes up: 

\frac{is}{of} =  \frac{percent}{100}


\frac{19.625}{490.625} =  \frac{percent}{100}


Cross multiplying and dividing by 490.625 will give a total of 4%.



4 0
3 years ago
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