See the picture attached to better understand the problem
we know that
90°+∠BAC=180°------> by supplementary angles
∠BAC=90°
125°+∠ABC=180° -----> by supplementary angles
∠ABC=55°
∠BAC+∠ABC+p=180----> <span>sum of the internal angles of a triangle is 180 degrees
</span>p=180-90-55-----> p=35°
the answer is
p=35°
we know that
90°+∠BAC=180°------> by supplementary angles
∠BAC=90°
125°+∠ABC=180° -----> by supplementary angles
∠ABC=55°
∠BAC+∠ABC+p=180----> <span>sum of the internal angles of a triangle is 180 degrees
</span>p=180-90-55-----> p=35°
the answer is
p=35°