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qaws [65]
3 years ago
10

Correct each sentence by writing the correct form of the underlined verb

Mathematics
1 answer:
dexar [7]3 years ago
8 0
Grammar isn't like math,
you have to sound it out to see if it makes sense.
1.splashes
2.fixs
3.catches
4.mix
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Find the value of x and the value of y.
stepladder [879]

Answer:

the 3rst one

Step-by-step explanation:

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Help can’t find the answer
mixer [17]

Answer:

Volume= 82.4in³

Step-by-step explanation:

Volume is the measure of the amount of space inside of a solid figure, like a cube, ball, cylinder or pyramid. It's units are always "cubic"

To find the volume of sphere, we will use the following formula of Volume:

Volume = 4/3 πr³

Put the values in the formula:

As we know that the value of π is 22/7 or 3.14

Radius = 2.7

According to the formula:

Volume = 4/3 * 3.14 *(2.7)³

Volume= 4/3* 3.14(19.683)

Volume=4/3(61.80462)

Volume=247.21848/3

Volume= 82.4in³....

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3 years ago
Como eu divido 3/4 por 20?
Juli2301 [7.4K]
Você pode, mas não receberá um bom número limpo. Eu recomendo que você faça divisão longa
3 0
3 years ago
"What is Limit of h (x) as x approaches 10 plus?"
Zepler [3.9K]

As <em>x</em> → 10 from above, <em>h(x)</em> is steadily approaching 18.5.

8 0
2 years ago
If logb2=x and logb3=y, evaluate the following in terms of x and y:
Alja [10]

log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x

<em><u>Solution:</u></em>

Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

a) log_b{162}

Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

log_b162 = x + 4y

Next

b) log_b 324

Break 324 down to primes:

324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

By rule 2

log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} =  3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} =  3x - 2y

Next

d) \frac{log_b27}{log_b16}

By rule 2

\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} =  3y - 4x

Thus the given are evaluated in terms of x and y

3 0
3 years ago
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