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Korvikt [17]
3 years ago
14

How to find the side length of a square

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0
Add all sides together to find the length of each side
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Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wan
Alborosie
Your Question:
<span>Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wants to give as much of her candy as she can to each of her six friends, and she wants to make sure they each get an equal number of pieces. How many pieces will be left over, if any, after Laurie gives her friends the candy?
My Answer:
If Laurie has four bags with ten pieces in each bag, and if her father gives her five more pieces,  she would have forty-five pieces and if she has six friends and wants to share it equally with six friends. Each friend would get 7 pieces.
My Work:
<span>45 ÷ 6 = 7.5 
</span>Hope I helped
♥ James.</span>
7 0
3 years ago
Read 2 more answers
X2 -20x + y^2 - 10y+25=0<br> identify center of the circle and radius
nlexa [21]

Answer:

Center of the circle = (10, 5)

Radius = 10

Step-by-step explanation:

Look at the picture

5 0
2 years ago
a spherical ball is inflated with helium at the rate of 100πft^3\min. how fast is the balloon's radius increasing at the instant
joja [24]
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8 0
3 years ago
Find all the solutions of the equation in the interval [0,2pi). 4sin^(2)x=5-4cosx
gulaghasi [49]
                       4sin²(x) = 5 - 4cos(x)
        4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
   4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
         4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
     4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
                2 - 2cos(2x) = 5 - 4cos(x)
              - 2                   - 2
                    -2cos(2x) = 3 - 4cos(x)
            -2[2cos²(x) - 1] = 3 - 4cos(x)
               -4cos²(x) + 2 = 3 - 4cos(x)
                               - 2  - 2
                     -4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
 4cos²(x) - 4cos(x) + 1 = 0
               [2cos(x) - 1]² = 0
                  2cos(x) - 1 = 0
                              + 1 + 1
                       2cos(x) = 1
                            2         2
                         cos(x) = ¹/₂
                cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
                                 x = 60, 300
                                 x = π/3, 5π/3

[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
5 0
2 years ago
Simplify 2 x 5^2. <br> A- 49<br> B- 20<br> C- 100<br> D- 50
IrinaK [193]
The answer to this question is 50
7 0
3 years ago
Read 2 more answers
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