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Anna35 [415]
3 years ago
7

Using the equation y=ax^2+bx+c to represent a parabola on a graph, which statement is true?

Mathematics
1 answer:
kifflom [539]3 years ago
5 0
The right answer is <span>(3) If a is positive, the parabola opens upwards</span>
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Widget wonders produces widgets. they have found that the cost, c(x), of making x widgets is a quadratic function in terms of x.
galben [10]
It's quadratic function, so  c(x) = ax^2 + bx + c. We know, that:

c(3) = 103    =>  3^2 a + 3b +c = 103   =>  9a+3b+c=103    (1)
c(7) = 163  =>  7^2 a + 7b + c = 163  =>  49a+7b+c=163   (2)
c(12)=328  =>  12^2 a + 12b + c = 328 => 144a+12b+c=328   (3)

From first equation you get  c = 103 - 9a - 3b
From second equation you get c = 163 - 49a - 7b
That's mean 
103 - 9a - 3b = 163 - 49a - 7b
40a+4b=60     |:4
10a+b=15  =>   b = 15 - 10a

Substitute now c = 103 - 9a - 3b to third equation. You get
144a+12b+103-9a-3b=328
135a+9b=225     |:9
15a+b=25
b=25-15a

If b=15-10a  and b=25-15a  that's  mean   

15-10a=25-15a
5a=10   |:5
a=2

b=25-15a=25 - 15*2=25-30 = -5

c= 103 - 9a - 3b = 103 - 9*2 - 3*(-5)=103-18+15=100

You get the function:

c(x)=2x^2-5x+100 \\ \\ \hbox{You have to find c(2):} \\ \\ c(2) =2 \cdot 2^2 - 5 \cdot 2 + 100 = 8-10+100=98

Answer: Total cost of producing 2 widgets is $98

8 0
3 years ago
universal pet house sells vinyl doghouses and treated lumber doghouses. it takes the company 5 hours to build a vinyl doghouse a
iragen [17]

5 hours to build 1 vinyl doghouse       
2 hours to build 1 lumber doghouse
1 hour to paint 1 vinyl doghouse
2 hours to assemble 1 lumber doghouse

Company hours = 50 hours/week
For assembly and painting = 30 hours/week

Let x = number of vinyl dog houses
      y = number of lumber dog houses

Build time = 5x
Build time = 2y
Paint time = x
Assembly time = 2y

Total time = 6x
                 = 4y
8 0
3 years ago
18- 12y = -22 -7y solve for y
Elenna [48]
Combine like terms: -7y+12y= 5y
18+22=40
Now: 5y=40
Get y alone: 5y/5=40/5
Y=8
8 0
4 years ago
Read 2 more answers
AD= 36 cm. Points C, B∈AD, such that AB:BC:CD=2:3:4. Find the distance of midpoints of the segments AB and CD.
brilliants [131]

Answer:

The distance of the midpoints of AB and CD is 24 cm

Step-by-step explanation:

The given information are;

The length of AD = 36 cm.

C and B are points on AD

The ratio of AB:BC:CD 2:3:4

The distance of the midpoints of segments AB and CD required

Therefore, we have the following proportion of the total length, 36

Segment AB = 2/(2 + 3 + 4) = 2/9×36 = 8 cm

Segment BC = 3/(2 + 3 + 4) = 3/9×36 = 12 cm

Segment CD = 4/(2 + 3 + 4) = 4/9×36 = 16 cm

The x-coordinate of the midpoint of segment AB = 4 cm

The x-coordinate of the midpoint of segment CD = 8 + 12 + 16/2 = 28 cm

Which gives;

The distance of midpoint of segment AB from A = 4 cm

The distance of midpoint of segment CD  from A = 28 cm

And the distance of the midpoints of AB and CD = 24 - 4 = 24 cm.

4 0
4 years ago
(X^2 - 8x + 12) / x- 6
Mice21 [21]

Answer:

X2x−14+12x

Step-by-step explanation:

8 0
3 years ago
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