Answer with Step-by-step explanation:
We are given that a function f(x) is continuous on (
).
1.f'(-1)=0 and f''(-1)=-7
We have to find information about f.
When f'(-1)=0 and f''(-1)=-7 < 0
Then, function is maximum at x=-1.
Therefore, at x=-1, f has local maximum.
Answer:a)at x=-1 ,f has local maximum.
2.) if f'(4)=0 and f''(4)=0
We know that when f''(x)=0 then test fails then the function has not maximum or minimum.
Therefore, at x=4 , f has not a maximum or minimum.
Answer:c) at x=4, f has not a maximum or minimum.
Answer:
x = 2 x = -6
Step-by-step explanation:
2 (x+2) ^2-4=28
Add 4 to each side
2 (x+2) ^2-4+4=28+4
2 (x+2) ^2= 32
Divide by 2
2/2 (x+2) ^2=32/2
(x+2)^2 = 16
Take the square root of each side
sqrt((x+2)^2) =±sqrt( 16)
x+2 = ±4
Subtract 2 from each side
x+2-2 = -2±4
x = -2±4
x = -2+4 and x = -2-4
x = 2 x = -6
Answer:
y - value of the vertex is 49.
Step-by-step explanation:
Given function is f(x) = -(x - 3)(x + 11)
f(x) = -(x² - 3x + 11x - 33)
= -(x² + 8x - 33)
= -(x² + 8x + 16 - 49)
= -[(x + 4)² - 49]
= -(x + 4)² + 49
Comparing this equation with the vertex form of a quadratic function,
f(x) = -(x - h)² + k
Where (h, k) is the vertex of the function.
Vertex of the parabola is (-4, 49)
Therefore, y-value of the vertex is 49.
Answer:
2/21x7/5 is 14/105
Step-by-step explanation:
Answer:
2x^3+3x^2+6x-4/x^2 +1
Step-by-step explanation:
