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valentina_108 [34]
3 years ago
13

Dakota mixes two cereals for breakfast. One gram of cereal A has 6 milligrams of sodium and 7 calories. One gram of cereal B has

8 milligrams of sodium and 5 calories. She wants the bowl of cereal to contain no more than 200 milligrams of sodium and 150 calories. Let "a" equal the number of grams of cereal A and "b" equal the number of grams in cereal B, where are "a" > 0 and "b" > 0. Which system of inequalities represents the possible ways Dakota can mix the cereals.
Mathematics
1 answer:
likoan [24]3 years ago
5 0

Number of grams of cereal A = a

Number of grams of cereal B = b

One gram of Cereal A has: 6 mg of sodium and 7 calories

One gram of Cereal A has: 8 mg of sodium and 5 calories

We need to make sure that the cereal contains maximum 200 mg sodium

⇒ Number of grams of cereal A × Sodium quantity in a gram of cereal A + Number of grams of cereal B × Sodium quantity in a gram of cereal B <= 200 mg

Substituting the required values

⇒ a×6 + b×8 <=200

Further simplifying the above equation

⇒ a×3 + b×4 <=100

Further, we need to make sure that the cereal contains maximum 150 calories

⇒ Number of grams of cereal A × Calories in a gram of cereal A + Number of grams of cereal B × Calories in a gram of cereal B <= 150

⇒ a×7 + b×5 <=150

Hence, the system of inequalities that represents the possible mix is:

a×3 + b×4 <=100 AND a×7 + b×5 <=150

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murzikaleks [220]

Answer:

Step-by-step explanation:

a  (2³)² = 2³ˣ² = 2⁶

b (7⁰)¹ = 7⁰ˣ¹ = 7⁰ = 1

c (5⁶)³ = 5⁶ˣ³ = 5¹⁸

d (6²)⁴ = 6²ˣ⁴ = 6⁸

e (8³)⁴ = 8³ˣ⁴ = 8¹²

f (4³)² = 4³ˣ² = 4⁶

g (9¹)² = 9¹ˣ² = 9² = 81

h (3⁷)² = 3⁷ˣ² = 3¹⁴

i (10²)³ = 10²ˣ³ = 10⁶

j (11²)⁴ = 11²ˣ⁴ = 11⁸

8 0
3 years ago
Which of these is greater than 5?<br> 2 2/5<br> 2 2/7<br> 1 7/8<br> 2 1/10<br> 2 5/8
Sauron [17]

Answer:

None of them are greater than 5. So the answer is false.

Hopes this helped!!!

7 0
4 years ago
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Dovator [93]

A would be your answer
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5 0
3 years ago
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GREYUIT [131]
This is a fairly tedious problem. The only way to solve that I see is to simply list out all the possible cases and go through each one by one. You'll use the triangle inequality theorem to see if the triangles can be formed. The theorem says that a+b > c must be true for all sets of pairs. In other words, take any two sides and add them up. The sum must be greater than the third side. 

Going through all the combos possible (that I could find), this is what I got
Blue9,Green7,Orange4
Blue9,Green7,Purple12
Blue9,Green7,Red3
Blue9,Green7,Yellow5
Blue9,Orange4,Purple12
Blue9,Purple12,Yellow5
Green7,Orange4,Yellow5
Green7,Red3,Yellow5
Orange4,Red3,Yellow5

In all, I count 9 cases. So the answer to problem 1 is 9.

-----------------------------------------------------------

For problem 2, the best way may be to pick two segments at a time instead of one. However, I have a feeling that will take just as long as the first method. I haven't tried it out. Even though going through the rods one at a time takes a while, it's probably the best option so you don't overlook any cases. 


6 0
4 years ago
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