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3 years ago

△MAH∼△WCF . What is the value of x?

Mathematics

2 answers:

spayn [35]3 years ago

8 0

Are there any choices that i can help with to solve the work problem

CaHeK987 [17]3 years ago

5 0

The answer is x=23. Sorry I am late.

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True or False?

oee [108]

Answer: it would be false.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

MODELING REAL LIFE There are a total of 64 students in a filmmaking club and a yearbook club. The filmmaking club has 14 more st

VashaNatasha [74]

Answer:

The system of linear equations is x + y = 64 and x = y + 14.

Given that,

The total number of students is 64 .

Here we assume the x be the number of students in filmmaking club .

And, y be the number of students in yearbook club.

Based on the above information, the calculation is as follows:

x + y = 64

And,

x = y + 14

Therefore,

We can say that

Number of students in yearbook club = 25

And, the number of students in filmmaking club = 39

3 0

2 years ago

Walter is mixing cement for his new patio . He knows he need to use a water-to-cement ratio of 20 to 30 . What percent of his to

kherson [118]

If his water to cement ratio is 20 to 30, this means that if he uses 20 liters of water, he'd use 30 liters of cement.

The total mixture would then be 20+30=50 liters.

and the water would be 20/50=0.4 or 40% of the total mixture.

5 0

3 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

90 POINTS! HELP PLEASE!!!! I need answers to a-e thank you.

polet [3.4K]

Answer:

(a)Equation representing amount of lights on Monday is 2 x + 3 y = 44

(b)Equation representing amount of lights on Tuesday is 5 x + 3 y = 56

(c) Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

Step-by-step explanation:

Let x = strands of lights on bushes.

Let y = strands of lights on trees.

Bob used 44 strands of light to decorate 2 bushes and 3 trees on Monday.

So, the number of light on 2 bushes = 2x

and the number of light on 3 tress = 3 y

⇒ 2 x + 3 y = 44

Also, On Tuesday, Bob used 56 strands of lights to decorate 5 bushes and 3 trees.

So, the number of light on 5 bushes = 5x

and the number of light on 3 tress = 3 y

⇒ 5 x + 3 y = 56

Now, solving the system of equations:

2 x + 3 y = 44

5 x + 3 y = 56

Subtract equation (2) from (1), we get

2 x + 3 y - (5 x + 3 y) = 44 - 56

or, 2x - 5x = - 12

or, 3x = 12 ⇒ x = 12/3 = 4 or x = 4

Using x = 4 in 2x + 3y = 44

2(4) + 3y = 44

or, 3y = 44- 8 = 36

or y = 36 /3 = 12 or y = 12

So, the value of x = 4, and y = 12

Hence, here Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

8 0

3 years ago