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Mice21 [21]
3 years ago
15

$7.80/h = cents/minutes

Mathematics
1 answer:
Nana76 [90]3 years ago
6 0
<span>$7.80/h = 780 cents / 60 minutes = 13 cents per minute</span>
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I need help on combining like terms, they make no sense whatsoever. Here are the questions: y + 4 + 3(y+2)..........z^2 + z+ 4z^
vodomira [7]
Y + 4 + 3(y+2)
y + 4 + 3y + 3*2
4y + 4 + 6
4y + 10

z^2 + z+ 4z^3 + 4z^2
5z^2 + z + 4z^3

1/4 (16 + 4p)
16/4 + 4p/4
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5 0
3 years ago
Factorise fully 24x^2 - 64x
Ulleksa [173]
This equation factored fully is

8x(3x-8)
4 0
4 years ago
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Which is the equation of a line that has a slope of 1/2 and passes through point (-2,3)
Gnesinka [82]

Answer:

y = 1/2x + 4

Step-by-step explanation:

8 0
3 years ago
find the slope of the curve y=x^2-2x-5 at the point P(2,5) by finding the limit of secant slopes through point P
Fynjy0 [20]

The point (2, 5) is not on the curve; probably you meant to say (2, -5)?

Consider an arbitrary point Q on the curve to the right of P, (t,y(t))=(t,t^2-2t-5), where t>2. The slope of the secant line through P and Q is given by the difference quotient,

\dfrac{(t^2-2t-5)-(-5)}{t-2}=\dfrac{t^2-2t}{t-2}=\dfrac{t(t-2)}{t-2}=t

where we are allowed to simplify because t\neq2.

Then the equation of the secant line is

y-(-5)=t(x-2)\implies y=t(x-2)-5

Taking the limit as t\to2, we have

\displaystyle\lim_{t\to2}t(x-2)-5=2(x-2)-5=2x-9

so the slope of the line tangent to the curve at P as slope 2.

- - -

We can verify this with differentiation. Taking the derivative, we get

\dfrac{\mathrm dy}{\mathrm dx}=2x-2

and at x=2, we get a slope of 2(2)-2=2, as expected.

4 0
3 years ago
What is the answer to:<br><br> x-2<br> ___= 3<br> 5
Alika [10]
(x - 2)/5 = 3

Multiply 5 to both sides:

x - 2 = 15

Add 2 to both sides:

x = 17
6 0
4 years ago
Read 2 more answers
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