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PolarNik [594]
3 years ago
11

Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0

Mathematics
2 answers:
IRISSAK [1]3 years ago
6 0

Answer:

The other answer is correct here except it is missing the answer 4pi/3

other wise its correct. The answers are 0, 2pi/3, and 4pi/3

Step-by-step explanation:

see previous answer

Jlenok [28]3 years ago
4 0
This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

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Please find the square roots of the following complex number.
Nana76 [90]

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

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6 0
2 years ago
Please help me answer this.
adoni [48]

Answer:

See explanation

Step-by-step explanation:

        Statements                         Reasons

1. \overline{AD}\parallel \overline{BC}                                        Given

2. \angle ADB\cong \angle CBD      As alternate interior angles when parallel lines AD and BC intersect by ltransversal BD

3. \overline{AD}\cong \overline{BC}                                     Given

4. \overline{BD}\cong \overline{DB}                     Reflexive property

5. \triangle ADB\cong \triangle CBD                  SAS postulate

6.  \angle ABD\cong \angle CDB              Corresponding parts of congruent triangles are congruent

7. \overline{AB}\parallel \overline{CD}            Inverse alternate interior angles theorem

8 0
2 years ago
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