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ELEN [110]
3 years ago
15

A number is decreased by 40% to 525. what is the original amount?​

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

The number is 875

Step-by-step explanation:

Step One:

Convert 40% to a decimal --> .40

Step Two

525 = n - .40n

(525 is equal to a number minus forty percent of a number )

Step Three

Isolate the variable by dividing each side by factors that don't contain the variable.

N = 875

zhenek [66]3 years ago
6 0

Answer:

875

Step-by-step explanation:

lets assume the original amount X

the new amount = X - ( X × 40% )

525 = (60 × X) ÷ 100

X = ( 525 × 100 ) ÷ 60

<u>X = 875</u>

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7 0
3 years ago
What is the relationship between 5 in these two numbers 8,523 and 9,852
babymother [125]

Answer:

The 5 in 8523 is 10x greater than the 5 in 9852.

Step-by-step explanation:

Note the place value of the two number's digit 5:

8<u>5</u>23: Hundreds place value.

98<u>5</u>2: Tens place value.

10 x 10 = 100 ∴ The 5 in 8523 (hundreds place value) is 10x greater than the 5 in 9852 (tens place value).

~

4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
trapecia [35]

Answer: 45 degrees

Step-by-step explanation: I just kinda eyeballed it, as a right angle cut in half in 45 degrees. Hope this helps!

6 0
2 years ago
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Xelga [282]

Answer:7/2

Step-by-step explanation:

8 0
3 years ago
Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0
Arada [10]

Answer:

b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0

Step-by-step explanation:

The given matrix addition is

B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

On equating both sides.

b_{11}+15=1\Rightarrow b_{11}=-14

b_{12}-7=2\Rightarrow b_{12}=9

b_{13}+4=12\Rightarrow b_{13}=8

b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

3 0
3 years ago
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