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kati45 [8]
3 years ago
14

What is the correct way to write three hundred nine million, fifty-eight thousand, three hundred four? A. 390,580,304 B. 309,58,

34 C. 309,058,304 D. 395,834
Mathematics
2 answers:
vovikov84 [41]3 years ago
5 0
I THINK IT`S C

hope i helped :0
Leni [432]3 years ago
3 0
C. 309,058,304

Three hundred nine million is in the millions bracket; wherein, three is in the hundred million place and nine is in the one million place.

fifty-eight thousand is in the thousands bracket; wherein 0 is placed in the hundred thousand place, five is in the ten thousands place, and eight is in the one thousands place.

three hundred four is placed as such because three should be in the hundreds place, 0 is in the tens place, and 4 is in the ones place.

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Answer:

\frac{a}{3} \frac{.}{.}\frac{3}{a} =1

Step-by-step explanation:

As we seen that the reciprocal of the a/3(a/3) provides the result as a product number that gives the output as 1 .

Also we know that two fractions number gives output 1 if they are the reciprocal or multiplicative inverse from each other.

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\frac{3a}{3a} \\\\it\ can\ be \ written \ as \\\frac{3}{a} \frac{.}{.}\frac{a}{3}=\ 1

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A manufacturer makes chocolate squares that have a target weight of 8 g. Quality control engineers sample 30 chocolate squares t
posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is \mu = 8.5.
  • The standard deviation is \sigma = 0.87.
  • A sample of 30 is taken, hence n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588.

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{8 - 8.5}{0.1588}

Z = -3.15

Z = -3.15 has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

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