<span>x =<span>−<span><span>2<span> and </span></span>y </span></span></span>=<span>−<span>2. Hope this helps</span></span>
        
             
        
        
        
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
 
        
             
        
        
        
Answer:
y = 2 
Step-by-step explanation:
20y - 21 = 10y - 1
20y = 10y + 20 
10y = 20 
y = 2 
 
        
             
        
        
        
Answer:
Option C
Step-by-step explanation:

![\sf log_w \ \dfrac{(x^{2}-6)^4}{\sqrt[3]{x^2+8} }=log_w \ (x^2-6)^4 - log_w(x^2+8)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csf%20log_w%20%5C%20%5Cdfrac%7B%28x%5E%7B2%7D-6%29%5E4%7D%7B%5Csqrt%5B3%5D%7Bx%5E2%2B8%7D%20%7D%3Dlog_w%20%5C%20%28x%5E2-6%29%5E4%20-%20log_w%28x%5E2%2B8%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
                        
 
        
             
        
        
        
Answer:
[a]. check attachment. 
[b]. It can not be said that the difference is ascribed to chance as P-value = 0.001 which is less than <<0.05. That is  P-value = 0.001 <<0.05.
Step-by-step explanation:
Without mincing words let's dive straight into the solution to the question above. 
[a]. The drawing showing the histogram of bacterial endotoxin levels is given in the attached picture. 
KINDLY NOTE: The data is right-skewed. 
[b].  ALLERGIC             MEAN        SE MEAN         STDEV           N
       FALSE                     1510             251                  1789            251
         TRUE                    530              109                 343               10
False - true = difference in a. 
Hence, 80 = estimated difference. 
For the difference, 95% CI = (434, 1527). 
DF = 58, P-value = 0.001, and the T value = 3.59. 
Therefore, It can not be said that the difference is ascribed to chance as P-value = 0.001 which is less than <<0.05. That is  P-value = 0.001 <<0.05.