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3 years ago

TriangleA′B′C′ is the image of triangleABC after a dilation.

Mathematics

2 answers:

hammer [34]3 years ago

7 0

Answer:

Step-by-step explanation:

The image A’B’C’ is scaled down by a factor of 1/3

ValentinkaMS [17]3 years ago

7 0

Answer:

the dilation from triangle A'B'C' to triangle ABC is 1/3

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The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

Please help me with this math problem.

mylen [45]

---|--/--/--|--/--/--|--/--/--|--/--/--|--/--/--|--/--/--|--/--/--|--/--/--|--/--/--|--/--/--|--------------
-5 -4-11/3-3 -2 -1 0 1 2 8/3 3 4 5
8/3≈ 2,6

-11/3 ≈-3,6

4 0

3 years ago

The sides of a triangle have lengths 4, 9, and 11. What kind of triangle is it?

aalyn [17]

Answer:Scalene Triangle

Step-by-step explanation:

In a scalene triangle,all sides are not equal

4 0

3 years ago

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I'm confused how do I simplify that??

zimovet [89]

The answer is simply 2x over 5(fraction) +1 so it the first choice

6 0

3 years ago

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the area of a rectangular pyramid is 65yd^2. the length of the playground is 3 yards longer than twice it's width. find the leng

schepotkina [342]

The area formula for a rectangle = Length x Width
Let length = L and width = W.
We also know that the length is 3 yards longer than twice it's width.
SO this means L = 3 PLUS 2 times W
L = 3 + 2W
Now plug that into the area formula and we get:
Area = (3 + 2W) x W
You'll need to multiply everything in the brackets by W.
So what would (3 + 2W)x W = ?

4 0

3 years ago