Answer:
(a) x = -2y
(c) 3x - 2y = 0
Step-by-step explanation:
You can tell if an equation is a direct variation equation if it can be written in the format y = kx.
Note that there is no addition and subtraction in this equation.
Let's put these equations in the form y = kx.
(a) x = -2y
- y = x/-2 → y = -1/2x
- This is equivalent to multiplying x by -1/2, so this is an example of direct variation.
(b) x + 2y = 12
- 2y = 12 - x
- y = 6 - 1/2x
- This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is <u>NOT</u> an example of direct variation.
(c) 3x - 2y = 0
- -2y = -3x
- y = 3/2x
- This follows the format of y = kx, so it is an example of direct variation.
(d) 5x² + y = 0
- y = -5x²
- This is not in the form of y = kx, so it is <u>NOT</u> an example of direct variation.
(e) y = 0.3x + 1.6
- 1.6 is being added to 0.3x, so it is <u>NOT</u> an example of direct variation.
(f) y - 2 = x
- y = x + 2
- 2 is being added to x, so it is <u>NOT</u> an example of direct variation.
The following equations are examples of direct variation:
Answer:im pretty sure its 64.8
Step-by-step explanation:
Answer: 22
Step-by-step explanation:
Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.
By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.
Answer: 33
Step-by-step explanation:
(f of g)(2) = f(g(2))
g(2) = -2(2) = -4
f(-4) = (-4)^2 - 3(-4) + 5 =
16 - - 12 + 5 =
16 + 17 =
33