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3 years ago

Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have

Mathematics

1 answer:

ryzh [129]3 years ago

5 0

Answer:

Ivan has 42 blue beads.

Step-by-step explanation:

We need to find how many blue beads Ivan has.

Blue beads = 6 times as many as red beans

b = 6r

r + b = 49

r + (6r) = 49

7r = 49

Divide both sides by seven to isolate r

r = 7

b = 6(7)

b = 42

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Let’s play Pick-A-Ball with replacement! There are 10 colored balls: 3 red, 4 white, and 3 blue. The balls have been placed into

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Answer:

0.48

Step-by-step explanation:

There are 10 colored balls: 3 red, 4 white, and 3 blue.

You selected 2 balls at random. They may be

RR, WW, BB, RW, RB, WB, WR, BR, BW.

To find the probability of selecting the color of ball that you just selected, find this probability in each of previous cases:

RR: (One red ball left and 8 balls left in total)

$P_{RR}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}$

WW: (Two white balls left and 8 balls left in total)

$P_{WW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{2}{8}=\dfrac{1}{30}$

BB: (One blue ball left and 8 balls left in total)

$P_{BB}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}$

RW: (Two red and three white balls left and 8 balls left in total)

$P_{RW}=\dfrac{3}{10}\cdot \dfrac{4}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

RB: (Two red and two blue balls left and 8 balls left in total)

$P_{RB}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}$

WB: (Two blue and three white balls left and 8 balls left in total)

$P_{WB}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

WR: (Two red and three white balls left and 8 balls left in total)

$P_{WR}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

BR: (Two red and two blue balls left and 8 balls left in total)

$P_{BR}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}$

BW: (Two blue and three white balls left and 8 balls left in total)

$P_{BW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

In total, the probability of selecting the color of ball that you just selected is

$\dfrac{1}{120}+\dfrac{1}{30}+\dfrac{1}{120}+2\cdot\dfrac{1}{12}+2\cdot \dfrac{1}{20}+2\cdot \dfrac{1}{12}=\\ \\=\dfrac{1}{120}+\dfrac{4}{120}+\dfrac{1}{120}+\dfrac{20}{120}+\dfrac{12}{120}+\dfrac{20}{120}=\dfrac{58}{120}=\dfrac{29}{60}\approx 0.48$

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The partial quotient is 23

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Read 2 more answers

Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have​

Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have