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liq [111]
3 years ago
5

The half-life of rhodium is about 30 seconds. you start with 500 grams. Write an equation

Mathematics
1 answer:
adoni [48]3 years ago
5 0

Half life is the period of time after which half amount of element is decayed.

Half life of rhodium = 30 sec

Amount of rhodium = 500 grams

how to write the equation, if we know the half life and starting or initial amount of rhodium is:

N = 500 g (1/2)^(t / 30 sec) 

t is the time and

<span>N is the amount of rhodium left at time t.</span>

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B angle 3 and 6 are complementary angles

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2. P(-4, 2), (6, 4), R(11, -2), S(2, -3)<br><br> is this is parallelogram or not??
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According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?
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Seven-thirds

Step-by-step explanation:

The give equation is f(x)=9x^8+9x^6-12x+7.

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The constant term is 7

According to the rational root theorem, the ratio of factors the constant terms to that of the coefficient of the leading term are all possible rational roots of the given polynomial.

Base on this theorem, \frac{7}{3} or seven thirds is a potential root because the numeration is a factor of 7 and the denominator is a factor of 9.

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A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
3 years ago
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