<span>C = 2πr
C = 2(2/7)(3.5)
= 22
Distance traveled by the wheel in one revolution is 22 feet.
Distance traveled in 500 revolutions will be: 500 x 22 = 11,000 feet.</span>
Answer:
7/30
Step-by-step explanation:
We are given that Seven-ninths (7/9) of the pencils in a box are yellow and three-tenths (3/10) of the yellow pencils are sharpened.
To find the fraction that represents sharpened yellow pencils, we find the product of the the fraction of yellow pencils and the fraction of yellow pencils that are sharpened.
That is:
=> (7 / 9) * (3 / 10)
=(7 * 3) / (9 * 10)
= 21 / 90
= 7 / 30
7/30 represents the fraction of sharpened yellow pencils.
Answer:
Here is the full proof:
AC bisects ∠BCD Given
∠CAB ≅ ∠CAD Definition of angle bisector
DC ⊥ AD Given
∠ADC = 90° Definition of perpendicular lines
BC ⊥ AB Given
∠ABC = 90° Definition of perpendicular lines
∠ADC ≅ ∠ABC Right angles are congruent
AC = AC Reflexive property
ΔCAB ≅ ΔCAD SAA
BC = DC CPCTC
The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

The second sum is simply the sum of N ones:

So, the final result is

which ends the proof.
<h2><u>
Answer with explanation:</u></h2>
The confidence interval for population mean (when population standard deviation is unknown) is given by :-

, where n= sample size
= Sample mean
s= sample size
t* = Critical value.
Given : n= 25
Degree of freedom : 

Significance level for 98% confidence interval : 
Using t-distribution table ,
Two-tailed critical value for 98% confidence interval :

⇒ The critical value that should be used in constructing the confidence interval = 2.4922
Then, the 95% confidence interval would be :-




Hence, the 98% confidence interval for the mean repair cost for the dryers. = 