Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y − 15 = 0 (x + 2)2 + (y + 3)2 = 18 5x2 + 5y2 − 10x + 20y − 30 = 0 (x + 1)2 + (y − 6)2 = 46 2x2 + 2y2 − 24x − 16y − 8 = 0 x2 + y2 + 2x − 12y − 9 = 0
2 answers:
Answer:
x2 + y2<em> </em>− 4x + 12y − 20 = 0 and (x-2)2 + (y+6)2 = 60
x2 + y2 + 2x - 12y - 9 = 0 and (x + 1)2 + (y - 6)2 = 46
2x2 + 2y2 - 24x - 16y - 8 = 0 and (x - 6)2 + (y - 4)2 = 56
3x2 +3y2 + 12x +18y - 15 = 0 and (x + 2)2 + (y + 3)2 = 18
I got a 100 on PLATO.
Step-by-step explanation:
The equation form of a circle is (x - a)² + (y - b)² = r²
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