Question

If x4 + 4y = 8xy, then dy/dx=

Answer 1

Step-by-step explanation:

x^4+4y=8xy

=>8xy-4y=x^4

=>4y(2x-1)=x^4

=>4y=x^4/(2x-1)

differentiating both side we got

4 dy/dx={4x^3(2x-1)-2x^4}/(2x-1)^2

i.e, dy/dx=(6x^4-4x^3)/4(2x-1)^2

=(6x^4-4x^3)/(16x^2-16x+4)

✌️:)